Required information |
Body weight (kilograms) = BW |
If patient is obese, use lean or ideal body weight* |
Hemoglobin concentration (g/dL) = Hgb |
Concentration of elemental iron in the parenteral product (mg/mL) = C¶ |
Assumptions |
Blood volume is 65 mL per kilogram |
Hemoglobin concentration to be corrected to 14 g/dL |
Each gram of hemoglobin contains 3.3 mg of iron |
Addition of iron for repletion of body stores is optional |
Intermediate calculations |
Blood volume (dL) = 65 (mL/kg) x body weight (kg) ÷ 100 (mL/dL) |
Hemoglobin deficit (g/dL) = 14 - patient hemoglobin concentration |
Hemoglobin deficit (g) = hemoglobin deficit (g/dL) x blood volume (dL) |
Iron deficit (mg) = hemoglobin deficit (g) x 3.3 (mg Fe/g Hgb) |
Volume of parenteral iron product required (mL) = iron deficit (mg) ÷ C (mg/mL) |
Final calculationsΔ |
Hemoglobin iron deficit (mg) = BW x (14 - Hgb) x (2.145) + iron to replenish stores if desired (mg) |
Volume of product required (mL) = BW x (14 - Hgb) x (2.145) ÷ C (if no added iron for stores) |
Example |
60 kg woman with a hemoglobin concentration of 8 g/dL. Parenteral iron product is iron sucrose (C = 20 mg elemental iron/mL). No additional iron to replenish stores. |
Hemoglobin iron deficit = 60 x (14 - 8) x (2.145) = 772 mg iron |
Volume of iron sucrose needed = 60 x (14 - 8) x (2.145) ÷ 20 = 38.6 mL◊ |
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